Problem 1. Multiples of 3 and 5

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

public class euler1 {
    public static void main(String[]args) {
        int N = 1000;
        int sum = 0;
        for (int i = 1; i < N; i++) {
            if (i % 3 == 0 || i % 5 == 0) {
                sum += i;
            }
        }
        System.out.println(sum);
    }
}